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Add option to start an app by its name

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By adding the '?' prefix, the app is searched by its name instead of its
package name (retrieving app names on the device may take some time):

    scrcpy --start-app=?firefox

An app matches if its label starts with the given name,
case-insensitive.

If '+' is also passed to force-stop the app before starting, then the
prefixes must be in that order:

    scrcpy --start-app=+?firefox

PR #5370 <https://github.com/Genymobile/scrcpy/pull/5370>
This commit is contained in:
Romain Vimont
2024-10-20 15:49:25 +02:00
parent dd20efa41c
commit 566b5be0f6
4 changed files with 60 additions and 5 deletions
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8
app/src/cli.c
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@@ -812,8 +812,14 @@ static const struct sc_option options[] = {
.longopt = "start-app",
.argdesc = "name",
.text = "Start an Android app, by its exact package name.\n"
"Add a '?' prefix to select an app whose name starts with the "
"given name, case-insensitive (retrieving app names on the "
"device may take some time):\n"
" scrcpy --start-app=?firefox\n"
"Add a '+' prefix to force-stop before starting the app:\n"
" scrcpy --new-display --start-app=+org.mozilla.firefox",
" scrcpy --new-display --start-app=+org.mozilla.firefox\n"
"Both prefixes can be used, in that order:\n"
" scrcpy --start-app=+?firefox",
},
{
.shortopt = 't',