noise: Disabled retry test for being way too flaky

This commit is contained in:
Christian Decker
2020-05-15 17:39:33 +02:00
parent 9b5a9076d4
commit 8668a2244d

View File

@@ -1,10 +1,12 @@
from binascii import hexlify
from onion import TlvPayload
from flaky import flaky
from pprint import pprint
from pyln.client import RpcError
from pyln.testing.fixtures import *
from pyln.testing.utils import wait_for
import hashlib
import unittest
import zbase32
@@ -30,7 +32,25 @@ def test_sendmsg_success(node_factory, executor):
assert(m2['verified'] == True)
@unittest.skipIf(True, "This test is flaky since we cannot force a payment to take a specific route")
def test_sendmsg_retry(node_factory, executor):
"""Fail a sendmsg using a cheap route, and check that it retries.
```dot
digraph {
l1 -> l2;
l2 -> l3;
l3 -> l4 [label = "fee-base=100'000"];
l2 -> l5;
l5 -> l4 [label = "fee-base=normal"];
}
```
By having a huge fee on the l3 -> l4 edge we force the initial attempt to
go through l1 -> l2 -> l5 -> l4, which should fail since l5 is offline (l1
should still be unaware about this).
"""
opts = [{'plugin': plugin}, {}, {'fee-base': 10000}, {'plugin': plugin}]
l1, l2, l3, l4 = node_factory.line_graph(4, opts=opts)
l5 = node_factory.get_node()
@@ -44,21 +64,23 @@ def test_sendmsg_retry(node_factory, executor):
return False
return True
wait_for(lambda: gossip_synced([l1, l2, l3, l4, l5]))
wait_for(lambda: [c['active'] for c in l1.rpc.listchannels()['channels']] == [True]*10)
# Now stop l5 so the first attempt will fail.
l5.stop()
recv = executor.submit(l4.rpc.recvmsg)
send = executor.submit(l1.rpc.sendmsg, l4.info['id'], "Hello world!")
# Just making sure our view didn't change since we initiated the attempt
assert([c['active'] for c in l1.rpc.listchannels()['channels']] == [True]*10)
pprint(l1.rpc.listchannels())
l1.daemon.wait_for_log(r'Retrying delivery')
sres = send.result(10)
assert(sres['attempt'] == 2)
pprint(sres)
print(recv.result(10))
msg = l4.rpc.recvmsg(last_id=-1)