mirror of
https://github.com/aljazceru/lightning.git
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We're about to slow down the invoice rpc (esp. under valgrind), which breaks the delicate timing of the autocleaninvoice test. Change that so the autocleaner (and timestamp) starts after the invoices are added. Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
321 lines
11 KiB
Python
321 lines
11 KiB
Python
from fixtures import * # noqa: F401,F403
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from lightning import RpcError
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from utils import only_one, DEVELOPER
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import pytest
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import time
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import unittest
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def test_invoice(node_factory):
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l1, l2 = node_factory.line_graph(2, fundchannel=False)
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addr1 = l2.rpc.newaddr('bech32')['address']
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addr2 = l2.rpc.newaddr('p2sh-segwit')['address']
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before = int(time.time())
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inv = l1.rpc.invoice(123000, 'label', 'description', '3700', [addr1, addr2])
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after = int(time.time())
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b11 = l1.rpc.decodepay(inv['bolt11'])
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assert b11['currency'] == 'bcrt'
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assert b11['created_at'] >= before
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assert b11['created_at'] <= after
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assert b11['payment_hash'] == inv['payment_hash']
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assert b11['description'] == 'description'
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assert b11['expiry'] == 3700
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assert b11['payee'] == l1.info['id']
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assert len(b11['fallbacks']) == 2
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assert b11['fallbacks'][0]['addr'] == addr1
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assert b11['fallbacks'][0]['type'] == 'P2WPKH'
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assert b11['fallbacks'][1]['addr'] == addr2
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assert b11['fallbacks'][1]['type'] == 'P2SH'
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# Check pay_index is null
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outputs = l1.db_query('SELECT pay_index IS NULL AS q FROM invoices WHERE label="label";')
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assert len(outputs) == 1 and outputs[0]['q'] != 0
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# Check any-amount invoice
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inv = l1.rpc.invoice("any", 'label2', 'description2')
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b11 = inv['bolt11']
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# Amount usually comes after currency (bcrt in our case),
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# but an any-amount invoices will have no amount
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assert b11.startswith("lnbcrt1")
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# By bech32 rules, the last '1' digit is the separator
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# between the human-readable and data parts. We want
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# to match the "lnbcrt1" above with the '1' digit as the
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# separator, and not for example "lnbcrt1m1....".
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assert b11.count('1') == 1
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def test_invoice_weirdstring(node_factory):
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l1 = node_factory.get_node()
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weird_label = 'label \\ " \t \n'
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weird_desc = 'description \\ " \t \n'
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l1.rpc.invoice(123000, weird_label, weird_desc)
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# FIXME: invoice RPC should return label!
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# Can find by this label.
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inv = only_one(l1.rpc.listinvoices(weird_label)['invoices'])
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assert inv['label'] == weird_label
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# Can find this in list.
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inv = only_one(l1.rpc.listinvoices()['invoices'])
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assert inv['label'] == weird_label
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b11 = l1.rpc.decodepay(inv['bolt11'])
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assert b11['description'] == weird_desc
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# Can delete by weird label.
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l1.rpc.delinvoice(weird_label, "unpaid")
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# We can also use numbers as labels.
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weird_label = 25
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weird_desc = '"'
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l1.rpc.invoice(123000, weird_label, weird_desc)
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# FIXME: invoice RPC should return label!
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# Can find by this label.
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inv = only_one(l1.rpc.listinvoices(weird_label)['invoices'])
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assert inv['label'] == str(weird_label)
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# Can find this in list.
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inv = only_one(l1.rpc.listinvoices()['invoices'])
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assert inv['label'] == str(weird_label)
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b11 = l1.rpc.decodepay(inv['bolt11'])
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assert b11['description'] == weird_desc
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# Can delete by weird label.
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l1.rpc.delinvoice(weird_label, "unpaid")
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def test_invoice_preimage(node_factory):
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"""Test explicit invoice 'preimage'.
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"""
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l1, l2 = node_factory.line_graph(2, announce=True)
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# I promise the below number is randomly generated
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invoice_preimage = "17b08f669513b7379728fc1abcea5eaf3448bc1eba55a68ca2cd1843409cdc04"
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# Make invoice and pay it
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inv = l2.rpc.invoice(msatoshi=123456, label="inv", description="?", preimage=invoice_preimage)
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payment = l1.rpc.pay(inv['bolt11'])
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# Check preimage was given.
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payment_preimage = payment['payment_preimage']
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assert invoice_preimage == payment_preimage
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# Creating a new invoice with same preimage should error.
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with pytest.raises(RpcError, match=r'preimage already used'):
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l2.rpc.invoice(123456, 'inv2', '?', preimage=invoice_preimage)
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def test_invoice_expiry(node_factory, executor):
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l1, l2 = node_factory.line_graph(2, fundchannel=True)
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inv = l2.rpc.invoice(msatoshi=123000, label='test_pay', description='description', expiry=1)['bolt11']
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time.sleep(2)
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with pytest.raises(RpcError):
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l1.rpc.pay(inv)
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invoices = l2.rpc.listinvoices('test_pay')['invoices']
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assert len(invoices) == 1
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assert invoices[0]['status'] == 'expired' and invoices[0]['expires_at'] < time.time()
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# Try deleting it.
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with pytest.raises(RpcError, match=r'Invoice status is expired not unpaid'):
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l2.rpc.delinvoice('test_pay', 'unpaid')
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with pytest.raises(RpcError, match=r'Invoice status is expired not paid'):
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l2.rpc.delinvoice('test_pay', 'paid')
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l2.rpc.delinvoice('test_pay', 'expired')
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with pytest.raises(RpcError, match=r'Unknown invoice'):
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l2.rpc.delinvoice('test_pay', 'expired')
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# Test expiration waiting.
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# The second invoice created expires first.
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l2.rpc.invoice('any', 'inv1', 'description', 10)
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l2.rpc.invoice('any', 'inv2', 'description', 4)
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l2.rpc.invoice('any', 'inv3', 'description', 16)
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creation = int(time.time())
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# Check waitinvoice correctly waits
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w1 = executor.submit(l2.rpc.waitinvoice, 'inv1')
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w2 = executor.submit(l2.rpc.waitinvoice, 'inv2')
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w3 = executor.submit(l2.rpc.waitinvoice, 'inv3')
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time.sleep(2) # total 2
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assert not w1.done()
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assert not w2.done()
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assert not w3.done()
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time.sleep(4) # total 6
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assert not w1.done()
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with pytest.raises(RpcError):
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w2.result()
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assert not w3.done()
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time.sleep(6) # total 12
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with pytest.raises(RpcError):
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w1.result()
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assert not w3.done()
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time.sleep(8) # total 20
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with pytest.raises(RpcError):
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w3.result()
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# Test delexpiredinvoice
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l2.rpc.delexpiredinvoice(maxexpirytime=creation + 8)
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# only inv2 should have been deleted
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assert len(l2.rpc.listinvoices()['invoices']) == 2
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assert len(l2.rpc.listinvoices('inv2')['invoices']) == 0
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# Test delexpiredinvoice all
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l2.rpc.delexpiredinvoice()
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# all invoices are expired and should be deleted
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assert len(l2.rpc.listinvoices()['invoices']) == 0
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@unittest.skipIf(not DEVELOPER, "Too slow without --dev-bitcoind-poll")
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def test_waitinvoice(node_factory, executor):
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"""Test waiting for one invoice will not return if another invoice is paid.
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"""
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# Setup
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l1, l2 = node_factory.line_graph(2)
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# Create invoices
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inv1 = l2.rpc.invoice(1000, 'inv1', 'inv1')
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inv2 = l2.rpc.invoice(1000, 'inv2', 'inv2')
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l2.rpc.invoice(1000, 'inv3', 'inv3')
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# Start waiting on invoice 3
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f3 = executor.submit(l2.rpc.waitinvoice, 'inv3')
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# Start waiting on invoice 1, should block
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f = executor.submit(l2.rpc.waitinvoice, 'inv1')
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time.sleep(1)
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assert not f.done()
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# Pay invoice 2
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l1.rpc.pay(inv2['bolt11'])
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# Waiter should stil be blocked
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time.sleep(1)
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assert not f.done()
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# Waiting on invoice 2 should return immediately
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r = executor.submit(l2.rpc.waitinvoice, 'inv2').result(timeout=5)
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assert r['label'] == 'inv2'
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# Pay invoice 1
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l1.rpc.pay(inv1['bolt11'])
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# Waiter for invoice 1 should now finish
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r = f.result(timeout=5)
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assert r['label'] == 'inv1'
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# Waiter for invoice 3 should still be waiting
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time.sleep(1)
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assert not f3.done()
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@unittest.skipIf(not DEVELOPER, "Too slow without --dev-bitcoind-poll")
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def test_waitanyinvoice(node_factory, executor):
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"""Test various variants of waiting for the next invoice to complete.
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"""
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l1, l2 = node_factory.line_graph(2)
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inv1 = l2.rpc.invoice(1000, 'inv1', 'inv1')
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inv2 = l2.rpc.invoice(1000, 'inv2', 'inv2')
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inv3 = l2.rpc.invoice(1000, 'inv3', 'inv3')
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# Attempt to wait for the first invoice
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f = executor.submit(l2.rpc.waitanyinvoice)
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time.sleep(1)
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# The call to waitanyinvoice should not have returned just yet
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assert not f.done()
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# Now pay the first two invoices and make sure we notice
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l1.rpc.pay(inv1['bolt11'])
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l1.rpc.pay(inv2['bolt11'])
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r = f.result(timeout=5)
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assert r['label'] == 'inv1'
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pay_index = r['pay_index']
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# This one should return immediately with inv2
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r = executor.submit(l2.rpc.waitanyinvoice, pay_index).result(timeout=5)
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assert r['label'] == 'inv2'
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pay_index = r['pay_index']
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# Now spawn the next waiter
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f = executor.submit(l2.rpc.waitanyinvoice, pay_index)
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time.sleep(1)
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assert not f.done()
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l1.rpc.pay(inv3['bolt11'])
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r = f.result(timeout=5)
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assert r['label'] == 'inv3'
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with pytest.raises(RpcError):
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l2.rpc.waitanyinvoice('non-number')
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def test_waitanyinvoice_reversed(node_factory, executor):
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"""Test waiting for invoices, where they are paid in reverse order
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to when they are created.
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"""
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# Setup
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l1, l2 = node_factory.line_graph(2)
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# Create invoices
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inv1 = l2.rpc.invoice(1000, 'inv1', 'inv1')
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inv2 = l2.rpc.invoice(1000, 'inv2', 'inv2')
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# Pay inv2, wait, pay inv1, wait
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# Pay inv2
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l1.rpc.pay(inv2['bolt11'])
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# Wait - should not block, should return inv2
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r = executor.submit(l2.rpc.waitanyinvoice).result(timeout=5)
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assert r['label'] == 'inv2'
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pay_index = r['pay_index']
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# Pay inv1
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l1.rpc.pay(inv1['bolt11'])
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# Wait inv2 - should not block, should return inv1
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r = executor.submit(l2.rpc.waitanyinvoice, pay_index).result(timeout=5)
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assert r['label'] == 'inv1'
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def test_autocleaninvoice(node_factory):
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l1 = node_factory.get_node()
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l1.rpc.invoice(msatoshi=12300, label='inv1', description='description1', expiry=4)
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l1.rpc.invoice(msatoshi=12300, label='inv2', description='description2', expiry=12)
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l1.rpc.autocleaninvoice(cycle_seconds=8, expired_by=2)
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start_time = time.time()
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# time 0
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# Both should still be there.
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assert len(l1.rpc.listinvoices('inv1')['invoices']) == 1
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assert len(l1.rpc.listinvoices('inv2')['invoices']) == 1
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assert l1.rpc.listinvoices('inv1')['invoices'][0]['description'] == 'description1'
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time.sleep(start_time - time.time() + 6) # total 6
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# Both should still be there - auto clean cycle not started.
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# inv1 should be expired
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assert len(l1.rpc.listinvoices('inv1')['invoices']) == 1
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assert only_one(l1.rpc.listinvoices('inv1')['invoices'])['status'] == 'expired'
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assert len(l1.rpc.listinvoices('inv2')['invoices']) == 1
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assert only_one(l1.rpc.listinvoices('inv2')['invoices'])['status'] != 'expired'
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time.sleep(start_time - time.time() + 10) # total 10
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# inv1 should have deleted, inv2 still there and unexpired.
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assert len(l1.rpc.listinvoices('inv1')['invoices']) == 0
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assert len(l1.rpc.listinvoices('inv2')['invoices']) == 1
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assert only_one(l1.rpc.listinvoices('inv2')['invoices'])['status'] != 'expired'
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time.sleep(start_time - time.time() + 14) # total 14
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# inv2 should still be there, but expired
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assert len(l1.rpc.listinvoices('inv1')['invoices']) == 0
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assert len(l1.rpc.listinvoices('inv2')['invoices']) == 1
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assert only_one(l1.rpc.listinvoices('inv2')['invoices'])['status'] == 'expired'
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time.sleep(start_time - time.time() + 18) # total 18
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# Everything deleted
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assert len(l1.rpc.listinvoices('inv1')['invoices']) == 0
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assert len(l1.rpc.listinvoices('inv2')['invoices']) == 0
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