pytest: protect against bad gossip messages from mining confirms too fast.

If we fund a channel between two nodes, then mine all the blocks to
announce it, any other nodes may see the announcement before the
blocks, causing CI to complain about "bad gossip":

```
lightningd-4: 2022-01-25T22:33:25.468Z DEBUG   032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e-gossipd: Ignoring future channel_announcment for 113x1x1 (current block 112)
lightningd-4: 2022-01-25T22:33:25.468Z DEBUG   032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e-gossipd: Bad gossip order: WIRE_CHANNEL_UPDATE before announcement 113x1x1/0
lightningd-4: 2022-01-25T22:33:25.468Z DEBUG   032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e-gossipd: Bad gossip order: WIRE_CHANNEL_UPDATE before announcement 113x1x1/1
lightningd-4: 2022-01-25T22:33:25.468Z DEBUG   032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e-gossipd: Bad gossip order: WIRE_NODE_ANNOUNCEMENT before announcement 032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e
```

Add a new helper for this case, and use it where there are more than 2 nodes.

Cleans up test_routing_gossip and a few other places which did this manually.

Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
This commit is contained in:
Rusty Russell
2022-01-30 14:07:23 +10:30
parent 6d9f6ffd67
commit e8d2176e6b
9 changed files with 77 additions and 82 deletions

View File

@@ -118,6 +118,17 @@ def sync_blockheight(bitcoind, nodes):
wait_for(lambda: n.rpc.getinfo()['blockheight'] == height)
def mine_funding_to_announce(bitcoind, nodes, num_blocks=5, wait_for_mempool=0):
"""Mine blocks so a channel can be announced (5, if it's already
mined), but make sure we don't leave nodes behind who will reject the
announcement. Not needed if there are only two nodes.
"""
bitcoind.generate_block(num_blocks - 1, wait_for_mempool)
sync_blockheight(bitcoind, nodes)
bitcoind.generate_block(1)
def wait_channel_quiescent(n1, n2):
wait_for(lambda: only_one(only_one(n1.rpc.listpeers(n2.info['id'])['peers'])['channels'])['htlcs'] == [])
wait_for(lambda: only_one(only_one(n2.rpc.listpeers(n1.info['id'])['peers'])['channels'])['htlcs'] == [])