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pytest: test for duplicate update_fee spam.

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Reported-by: @pm47
Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
This commit is contained in:
Rusty Russell
2019-06-08 12:27:25 +09:30
parent b6b548a983
commit d344f9d267
1 changed files with 23 additions and 0 deletions
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23
tests/test_connection.py
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@@ -1690,3 +1690,26 @@ def test_change_chaining(node_factory, bitcoind):
with pytest.raises(RpcError): with pytest.raises(RpcError):
l1.rpc.fundchannel(l3.info['id'], 10**7) # Defaults to minconf=1 l1.rpc.fundchannel(l3.info['id'], 10**7) # Defaults to minconf=1
l1.rpc.fundchannel(l3.info['id'], 10**7, minconf=0) l1.rpc.fundchannel(l3.info['id'], 10**7, minconf=0)
@pytest.mark.xfail(strict=True)
def test_feerate_spam(node_factory):
l1, l2 = node_factory.line_graph(2)
# Pay almost everything to l2.
l1.pay(l2, 10**9 - 25000000)
# It will send this once (may have happened before line_graph's wait)
wait_for(lambda: l1.daemon.is_in_log('Setting REMOTE feerate to 15000'))
wait_for(lambda: l1.daemon.is_in_log('peer_out WIRE_UPDATE_FEE'))
# Now change feerates to something l1 can't afford.
l1.set_feerates((100000, 100000, 100000))
# It will raise as far as it can (20000)
l1.daemon.wait_for_log('Setting REMOTE feerate to 20000')
l1.daemon.wait_for_log('peer_out WIRE_UPDATE_FEE')
# But it won't do it again once it's at max.
with pytest.raises(TimeoutError):
l1.daemon.wait_for_log('peer_out WIRE_UPDATE_FEE', timeout=5)