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pytest: test closing one multichannel works as expected.

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Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
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Rusty Russell
2022-03-23 09:31:35 +10:30
parent 4e8239fcfe
commit 8458994a7f
1 changed files with 17 additions and 0 deletions
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17
tests/test_connection.py
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@@ -3864,3 +3864,20 @@ def test_multichan(node_factory, executor, bitcoind):
assert chan23a['short_channel_id'] == scid23a assert chan23a['short_channel_id'] == scid23a
assert chan23b['amount_msat'] == Millisatoshi(1001000000) assert chan23b['amount_msat'] == Millisatoshi(1001000000)
assert chan23b['short_channel_id'] == scid23b assert chan23b['short_channel_id'] == scid23b
# We can close one, other one is still fine.
with pytest.raises(RpcError, match="Peer has multiple channels"):
l2.rpc.close(l3.info['id'])
l2.rpc.close(scid23b)
bitcoind.generate_block(1, wait_for_mempool=1)
# Gossip works as expected.
wait_for(lambda: len(l1.rpc.listchannels(source=l3.info['id'])['channels']) == 1)
assert only_one(l1.rpc.listchannels(source=l3.info['id'])['channels'])['short_channel_id'] == scid23a
# We can actually pay by *closed* scid (at least until it's completely forgotten)
route[1]['channel'] = scid23a
inv = l3.rpc.invoice(100000000, "invoice3", "invoice3")
l1.rpc.sendpay(route, inv['payment_hash'], payment_secret=inv['payment_secret'])
l1.rpc.waitsendpay(inv['payment_hash'])