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Bitcoind should always eventually finish starting, but there is no guarantee on how long it takes, so don't apply a time-out. In case bitcoind hangs indefinitely, the test will hang indefinitely too, but this should be solved in bitcoind, not in the test code.
This commit is contained in:
committed by
Christian Decker
parent
859070a5ed
commit
0b0708d86a
@@ -127,6 +127,8 @@ class TailableProc(object):
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starting from last of the previous waited-for log entries (if any). We
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starting from last of the previous waited-for log entries (if any). We
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fail if the timeout is exceeded or if the underlying process
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fail if the timeout is exceeded or if the underlying process
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exits before all the `regexs` were found.
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exits before all the `regexs` were found.
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If timeout is None, no time-out is applied.
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"""
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"""
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logging.debug("Waiting for {} in the logs".format(regexs))
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logging.debug("Waiting for {} in the logs".format(regexs))
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exs = [re.compile(r) for r in regexs]
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exs = [re.compile(r) for r in regexs]
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@@ -134,8 +136,8 @@ class TailableProc(object):
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pos = self.logsearch_start
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pos = self.logsearch_start
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initial_pos = len(self.logs)
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initial_pos = len(self.logs)
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while True:
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while True:
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if time.time() > start_time + timeout:
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if timeout is not None and time.time() > start_time + timeout:
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print("Can't find {} in logs".format(exs))
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print("Time-out: can't find {} in logs".format(exs))
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for r in exs:
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for r in exs:
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if self.is_in_log(r):
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if self.is_in_log(r):
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print("({} was previously in logs!)".format(r))
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print("({} was previously in logs!)".format(r))
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@@ -223,7 +225,7 @@ class BitcoinD(TailableProc):
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def start(self):
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def start(self):
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TailableProc.start(self)
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TailableProc.start(self)
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self.wait_for_log("Done loading", timeout=10)
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self.wait_for_log("Done loading", timeout=None)
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logging.info("BitcoinD started")
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logging.info("BitcoinD started")
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