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_posts/2016-06-11-mdam.md

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+---
+layout: post
+title:  "Find Substrings for line Encoding [CF]"
+date:   2016-06-11 03:04:23 +0700
+categories: [python, codefights]
+---
+
+Given a string, return its encoding defined as follows:
+
+First, the string is divided into the least possible number of disjoint **substrings** consisting of identical characters
+for example, `"aabbbc"` is divided into `["aa", "bbb", "c"]`
+Next, each substring with length greater than one is replaced with a concatenation of its length and the repeating character
+for example, substring `"bbb"` is replaced by `"3b"`
+Finally, all the new strings are concatenated together in the same order and a new string is returned.
+
+####SUBSTRING
+
+A **substring** of a string `S` is another string `S'` that occurs in `S`. For example, `"Fights"` is a substring of `"CodeFights"`, but `"CoFi"` isn't.
+
+**Example**
+
+For `s = "aabbbc"`, the output should be `lineEncoding(s) = "2a3bc"`.
+
+**Input/Output**
+
+    * [time limit] 4000ms (py)
+    * [input] string s (String consisting of lowercase English letters.)
+
+    _Constraints:_ `4 ≤ s.length ≤ 15.`
+
+    * [output] string
+
+    Encoded version of s.
+
+**Solution:**
+
+```python
+import re
+def lineEncoding(s):
+    grub = [ m.group(0) for m in re.finditer(r"(\w)\1*", s )]
+    numb = 0
+    out  = []
+    for i in grub:
+        numb += 1
+        if len(i) > 1:
+            out.append(grub[numb-1].replace(grub[numb-1], str(len(i))+i[0]))
+        else:
+            out.append(i)
+    return ''.join(out)
+```
+
+**Result Tests:**
+
+```python
+>>>
+s = "aabbbc"
+>>> lineEncoding(s)
+"2a3bc"
+>>>
+>>> s = "abbcabb"
+>>> lineEncoding(s)
+"a2bca2b"
+>>>
+>>> s = "abcd"
+>>> lineEncoding(s)
+"abcd"
+>>>
+```